February 2019 0 58 Report
Wiadomo, że cos \alpha = \frac{ \sqrt{21} }{5} wówczas wartość wyrażenia  \frac{sin^2 \alpha }{tg^2 \alpha } ( \frac{1 }{1- sin^2 \alpha } -1) = cos \alpha = \frac{ \sqrt{21} }{5} jest równa :
A) 1 - \sqrt{2/5} B)  \frac{4}{25} C)  \frac{3}{5}  D)  \frac{21}{25}
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