Wiadomo, że Log5 11= a . Wykaż, że Log 121 5 pierwiastek z5 = 3 : 4a
log₅11=a log₁₂₁5√5=log₅5√5/log₅121 log₁₂₁5√5=3/2 log₅5/2log₅11 log₁₂₁5√5=¾a bo 3/2:2 = 3/2*½= ¾
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log₅11=a
log₁₂₁5√5=log₅5√5/log₅121
log₁₂₁5√5=3/2 log₅5/2log₅11
log₁₂₁5√5=¾a bo 3/2:2 = 3/2*½= ¾