September 2018 2 23 Report

Wartość bezwzględna .

Uprość wyrażenia:

1.

\sqrt{12-6\sqrt{3}} =

2.

\sqrt{(5-\sqrt{6})^2}=

3.

\sqrt{21+8\sqrt{5}}=

4.

\sqrt{7-2\sqrt{6}}=

PS; Podpowiedz:

\sqrt{3+2\sqrt{2}} = \sqrt{1+2\sqrt{2}+(\sqrt{2})^2} = \sqrt{(1+\sqrt{2})^2} = |1+\sqrt{2}|


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