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2Ag2o=O2 + 4Ag
Nastepnie obliczamy mase molowe
M Ag20= 2*108 + 16 =232g/mol
M Ag = 108g/mol
No i z proporcji(patrzac na równanie reakcji)
2*232-4*108
4,64- x
x=4,32g tyle:)