w trojkacie rozwartokatnym ABC: |AB| = 4 cm i |AC| = 8 cm. Kat przy wierzcholku A ma 30⁰. oblicz pole tego trojkata
P=1/2absinα
P=1/2*4*8*sin30
P=16*1/2
P=8
P= 1/2 * a*b*sin kąta alfap= 1/2* 4*8* 0,5= 8 ---- pole
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
P=1/2absinα
P=1/2*4*8*sin30
P=16*1/2
P=8
P= 1/2 * a*b*sin kąta alfa
p= 1/2* 4*8* 0,5= 8 ---- pole