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12cm-5cm=8cm
P=(a+b)*h/2
P=12*8/2
P=96/2
P=48cm²
:)
h<--wysokość
a+b<--suma podstaw
*<---razy
a+b=1.2dm=12cm
h=12cm-5cm=7cm
P=0.5h(a+b)
P=0.5*12cm*7cm=6cm*7cm=42cm²
Odp. Pole tego trapezu wynosi 42 centymetry kwadratowe.
12cm-5=7cm
P=(a+b)× h÷2
P=(6+6)×7 ÷ 2
P=36× 7 = 252÷ 2=126cm