W trapezie o polu 26 cm kwadratowych , jedna z podstaw ma 3 cm a wysokość 4cm . Oblicz długość 2 podstawy !
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P= (a+b) x h
____________
2
26 = ( 3 + ? ) x 4
______________
2
26 = ( 3 + ? ) x 2
26 : 2 = ( 3 + ? )
13 = ( 3 + ? )
13 - 3 = 10
Odp. Druga podstawa wynosi 10 cm.
a=3cm
b=?
P=26cm^
h=4cm
P=1/2 * h * (a+b)
26cm^ = 1/2 * 4cm * ( 3cm + b)
26cm^ = 2cm * ( 3cm + b)
3cm + b = 26cm^ : 2cm
3 cm + b = 13cm
b = 13cm - 3cm = 10cm