W prostokącie ABCD bok AB ma dlugość 8 cm, a bok BC jest o 2cm krótszy od przekątnej BD. Oblicz obwód prostokąta ABCD.
(x-2)^2+8^2=x^2
x^2-4+64=x^2
2x^2=60
x^2=30
x=√30
Obw= 2*8+2√30= 16+2√30
a = 8 cm
d = b+2
b = ?
Obw = ?
Z tw.Pitagorasa:
d^2 = a^2 + b^2
(b+2)^2 = 8^2+b^2
b^2 + 4b + 4 = 64+b^2
4b = 64 - 4
4b = 60 /:4
b = 15 cm
Obw = 2(a+b) = 2(8cm+15cm) = 2 *23 cm
Obw = 46 cm
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(x-2)^2+8^2=x^2
x^2-4+64=x^2
2x^2=60
x^2=30
x=√30
Obw= 2*8+2√30= 16+2√30
a = 8 cm
d = b+2
b = ?
Obw = ?
Z tw.Pitagorasa:
d^2 = a^2 + b^2
(b+2)^2 = 8^2+b^2
b^2 + 4b + 4 = 64+b^2
4b = 64 - 4
4b = 60 /:4
b = 15 cm
Obw = 2(a+b) = 2(8cm+15cm) = 2 *23 cm
Obw = 46 cm
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