" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
c = 2R
sin(a) = b/c => b = sin(a)2R
cos(a) = a/c => a = cos(a)2R
Obwód = 2R + 2Rcos(a) + 2Rsin(a) = 2R(1 + sin(a) + cos(a)
Pole: [sin(a)2R * cos(a)2R] / 2
= [sin(a)cos(a)R^2]
P = r(a + b + c)/2
2[sin(a)cos(a)R^2] = r[2R(1+ sin(a) + cos(a)]
r =[ sin(a)cos(a)R ]/ [ 1 + sin(a) + cos(a)
Powinno być dobrze, może drobne sprawy kosmetyczne ale rachunkowo powinno być dobrze