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p₁/T₁=p₂/T₂
p₂=(p₁*T₂)/T₁
Δp=p₂-p₁
p1 * v1/t1 = p2*v2/t2 t1=t2 zatem
p1/t1 = p2/t2
p2=p1*t2/t1
p2-p1=p1*t2/t1 - p1
zakladam ze t1 i t2 jest w K
p1/t1=p2/t2
p1*t2=p2*t1
p2=p1*t2/t1
Δp=p2-p1=p1(t2/t1-1)
Gdy t1,t2 stop Celzjusza to:
Δp=p2-p1=p1[(t2+273)/(t1+273)-1]
pozdrawiam
Hans