W ilu dm3 tlenku chloru(I) (Cl2O) (warunki normalne) jest zawarta taka sama ilosc chloru co w 6,75g tlenku chloru (IV) (ClO2) ? Musi wyjść 1,12dm3 :)
z góry dzięki ;d
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mCl=35,5u
mClO2=67,5u
67,5g ClO2-------35,5g chloru
6,75g ClO2----------xg chloru
x = 3,55g chloru
22,4dm3 Cl2O-------71g chloru
xdm3 Cl2O-----------3,55g chloru
x = 1,12dm3 Cl2O