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l=10pi
5*5=25
10pi*25=250pi=785
Pokonuje drogę 785m.
Ob=2πr
r=5m
Ob=2π*5
Ob=10πm
Droga w 1 min= 5*Ob
s=5*10π
s=50πm
Droga w 5 min
s=5 * 50πm
s=250πm
5min = 25 obrotów
Obwod = l=2pi*r
l= 2*3,14*5 = 6,28 * 5 = 31,4
n(obroty) = 25
d(droga) = x
obroty * obwod = droga
25 * 31,4 = 785m.
Odp. Chłopiec w ciagu 5 min pokonuje droge 785m.