w 800cm3 roztworu znajduje sie 83 g jodku potasu KJ.Oblicz stężenie molowe tego roztworu.
Cm=n/VM KI = 166g/mol166 - 1
83 - xx=0.5Cm=0.5/800Cm=0,000625
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Cm=n/V
M KI = 166g/mol
166 - 1
83 - x
x=0.5
Cm=0.5/800
Cm=0,000625