w 200g wody rozpuszczono 0,3 mola NaOH. OBlicz stężenie procentowe otrzymanego roztworu
m H2O = 200g
mr = 200 + ms
1 mol NaOH --- 40g
0,3mol -----------x
x=ms= 12g
mr = 212g
Cp= (ms/mr) *100% = (12/212) * 100% = 5,66%
Pozdrawiam!
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m H2O = 200g
mr = 200 + ms
1 mol NaOH --- 40g
0,3mol -----------x
x=ms= 12g
mr = 212g
Cp= (ms/mr) *100% = (12/212) * 100% = 5,66%
Pozdrawiam!