W 1dm^3 osocza krwi znajduje się 3g jonów sodu Na+. Ile wynosi stężenie molowe jonów sodu w osoczu krwi .?
M Na(+)=23g/mol
1mol Na(+)------23g
xmoli Na(+)------3g
x = 0,13mola Na(+)
n=0,13mola
v=1dm3
Cm=n/v
Cm=0,13/1
Cm = 0,13mol/dm3 Na(+)
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M Na(+)=23g/mol
1mol Na(+)------23g
xmoli Na(+)------3g
x = 0,13mola Na(+)
n=0,13mola
v=1dm3
Cm=n/v
Cm=0,13/1
Cm = 0,13mol/dm3 Na(+)