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t² = 10² - 6²
t² = 100 - 36
t = √64
t = 8 cm
V = 1/3 . π . r² . t
V = 1/3 . 3,14 . 6² . 8
V = 301,44 cm³
r= 6cm
s=10 cm
dit:volume...?
penyelesaian:
∵tinggi kerucut
t²=s²-r²
t²=10²-6²
t²=100-36
t²=64
t=√64
t=8 cm
∵volume kerucut
V= π r² t
V=1/3 × 3,14 × (6cm)² × 8 cm
V=1/3 × 3,14 ×36cm²×8 cm
V=301,44 cm³