Volume sebuah kerucut adalah 588,75 mm3. Jika jari jarinya 7,5 mm , tingginya adalah
ananekusuma21
V kerucut = 588,75 1/3 x phi x r² x t = 588,75 1/3 x 3,14 x 7,5² x t = 588,75 1/3 x 3,14 x 56,25 x t = 588,75 18,75 x 3,14 x t = 588,75 58,875 x t = 588,75 t = 588,75 : 58,875 t = 10 mm
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anindyaar
V = 1/3× L alas × t 588,75 = 1/3 × phi × r² × t 588,75 = 1/3× 3,14 × 7,5 × 7,5 × t 588,75 =1/3× 176,625 × t 588,75=58,875 × t t=588,75 : 58,875 t=10 mm semoga membantu
1/3 x phi x r² x t = 588,75
1/3 x 3,14 x 7,5² x t = 588,75
1/3 x 3,14 x 56,25 x t = 588,75
18,75 x 3,14 x t = 588,75
58,875 x t = 588,75
t = 588,75 : 58,875
t = 10 mm
588,75 = 1/3 × phi × r² × t
588,75 = 1/3× 3,14 × 7,5 × 7,5 × t
588,75 =1/3× 176,625 × t
588,75=58,875 × t
t=588,75 : 58,875
t=10 mm
semoga membantu