.volume sebuah kerucut 314cm2 .jika panjang diameter alasnya 10cm maka tentukan panjang garis pelukis kerucut tersebut??: )
5dregensleyer
Volum = 1/3 x π x r² x t 314 = 1/3 x 3,14 x 5² x t 314 = 1/3 x 3,14 x 25 x t 314 = 1/3 x 78,5t 314 = 26,16t 314/26,16 = t 12 = t garis pelukis (s) s = √12² + 5² = √144+25 = √169 = 13 cm
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balaputradewar
R=1/2D=1/2.10=5 cm v=1/3πr².t 314=1/3.3,14.5².t 314.3=78,5t 942=78,5t 942/78,5=t 12=t
314 = 1/3 x 3,14 x 5² x t
314 = 1/3 x 3,14 x 25 x t
314 = 1/3 x 78,5t
314 = 26,16t
314/26,16 = t
12 = t
garis pelukis (s)
s = √12² + 5²
= √144+25
= √169
= 13 cm
v=1/3πr².t
314=1/3.3,14.5².t
314.3=78,5t
942=78,5t
942/78,5=t
12=t
s=√r²+t²
s=√5²+12²
s=√25+144
s=√169
s=13 cm