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1800 = 15.6.t
1800 = 90.t
t = 1800/90
t = 20 cm
jadi,
Lp balok = 2.(pl+pt+lt)
= 2.(15.6 + 15.20 + 6.20)
= 2.(90+300+120)
= 2.510
= 1020 cm²
t = V : p : l
= 1.800 cm³ : 15 cm : 6 cm
= 20 cm
Sehingga, luas permukaan balok :
Lp = 2 ( pl + pt + lt )
= 2 ( 15 cm × 6 cm + 15 cm × 20 cm + 6 cm × 20 cm )
= 2 ( 90 cm² + 300 cm² + 120 cm² )
= 2 × 510 cm²
= 1.020 cm²