Volume kerucut yang keliling alasnya 251,2 cm, panjang garis pelukisnya 50 cm, dan pendekatan fi= 3,14 adalah....
FredrickTanW
251,2=2 X 3.14 X r 251,2 = 6.28r r = 251,2/6.28 r = 40 akar 50 pangkat 2 - 40 pangkat 2 akar 2500-1600 akar = 900 akar = 30 1/3 X 3.14 X 40 PANGKAT 2 X 30 = 50240
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jinan
Kel = 2.phi.r 251,2 = 2.3,14.r 251/3,14 = 2.r r = 80/2 r = 40 cm
t² = s² - r² t² = 50² - 40² t² = 2500 - 1600 t = √900 t = 30 cm
251,2 = 6.28r
r = 251,2/6.28
r = 40
akar 50 pangkat 2 - 40 pangkat 2
akar 2500-1600
akar = 900
akar = 30
1/3 X 3.14 X 40 PANGKAT 2 X 30
= 50240
251,2 = 2.3,14.r
251/3,14 = 2.r
r = 80/2
r = 40 cm
t² = s² - r²
t² = 50² - 40²
t² = 2500 - 1600
t = √900
t = 30 cm
v = 1/3.phi.r².t
= 1/3.3,14.40².30
= 3,14.40.400
= 125,6.400
= 50240 cm³