Volume benda putar yang terbentuk jika daerah yang dibatasi kurva y = x+2, sumbu x, garis x=0, dan garis x = 3 diputar mengelilingi sumbu x sejauh 360 adalah........ satuan volume
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integral (x+2)² dx =integral(x²+4x+4)dx= (1/3 x³+2x²+4x) batasnya 0 dan 3
maka(1/3 3³+2.3²+4.3) - (1/3 0³+2.0²+4.0)=9+18+12=39 sat vol
diketahui:
batas atas: 3
batas bawah: 0
ʃ y² dx
= ʃ (x + 2)² dx
= ʃ x² + 4x + 4 dx
= 1/3 x³ + 2x² + 4x, masukkin batas atas dan bawah
= [1/3 x³ + 2x² + 4x] - [1/3 x³ + 2x² + 4x]
= [1/3 (3)³ + 2(3)² + 4(3)] - [1/3 0³ + 2(0)² + 4(0)]
= [1/3 27 + 2(9) + 12] - [1/3 0 + 2(0) + 4(0)]
= [9 + 18 + 12] - [0 + 0 + 0]
= 39 - 0
= 39
jadiin yang terbaik kalau membantu :p