" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
**a² - b² = (a - b)(a+b)
oraz
***sin²α + cos²α = 1, stąd sin²α = 1 - cos²α
sin⁴α-cos⁴α = z ** = (sin²α- cos²α)(sin²α + cos²α )= (z ***) =
= (sin²α - cos²α) * 1 = (znów z *** ( podstawiamy za sin²α)) =
= 1 - cos²α - cos²α = 1 - 2 cos²α
Bez opisu:
sin⁴α-cos⁴α = (sin²α- cos²α)(sin²α + cos²α ) = (sin²α - cos²α) * 1 =
= 1 - cos²α - cos²α = 1 - 2 cos²α
co nalezało wykazać.