Uzasadnij, że dla każdego kąta ostrego alpha zachodzi związek:
sin^2 alfa (1+ctg^2 alfa)=1
Wzoru
sin²α+cos²α=1
ctgα=cosα/sinα
------------------
sin²α(1+ctg²α)=1
L=sin²α(1+cos²α/sin²α)=
=sin²α+cos²α=
=1=P
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Wzoru
sin²α+cos²α=1
ctgα=cosα/sinα
------------------
sin²α(1+ctg²α)=1
L=sin²α(1+cos²α/sin²α)=
=sin²α+cos²α=
=1=P
licze na naj