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V=0,2dm³
Cm=0,1mol/dm³
NaBr => 103 g/mol
Cm=ms/Mr*V
ms=Cm*Mr*V
ms=0,1*0,2*103=2,06 g
V=0,2 dm³
Cmolowe=0,1 mol/dm³
Ms-masa substancji
Mm-masa molowa
Cmolowe=Ms/Mm*V
Ms=Cmolowe*Mm*V
Mm=23+80=103 g/mol
Ms=2,06g