Usuń niewymiernośc z mianownika a) 8-pierwiastek z 2 i na dole pierwiastek 3. b) 11- pierwiastek 3 i na dole 1+ pierwiastek 3 Proszę zrobić teraz szybko
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8-√2 √3 8√3 - √6
------- * ------ = ----------
√3 √3 3
11-√3 1-√3 11-11√3-√3+3 14 - 12√3 -2(-7+6√3)
---------- * ---------- = --------------------- = --------------= -----------------=
1 + √3 1-√3 1 - 3 -2 -2
= -7+6√3 = 6√3 - 7
(8-sqrt2)/sqrt3 * sqrt3/sqrt3 = [sqrt3*(8-sqrt2)]/3 =(8sqrt3-sqrt6)/3
(11-sqrt3)/(1+sqrt3) * (1-sqrt3)/(1-sqrt3)=[(11-sqrt3)*(1-sqrt3)/(1-3)=(11-11sqrt3-sqrt3+3)/-2=-(14-12sqrt3)/2=6sqrt3-7