Ustal wzór alkoholu o masie 46u. PILNE!!!
etanol wzór to C2H5OH
46u - 17u (OH) = 29u
29u / 12 = 2 reszta 5
2atomy węgla i 5 atomów wodoru
liczę na naj
CnH2n+1OH = 46u
12n+2n+1+16+1 = 46
14n = 28
n = 2
C2H5OH
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etanol wzór to C2H5OH
46u - 17u (OH) = 29u
29u / 12 = 2 reszta 5
2atomy węgla i 5 atomów wodoru
liczę na naj
CnH2n+1OH = 46u
12n+2n+1+16+1 = 46
14n = 28
n = 2
C2H5OH