Ustal skład reszty monocukrowej w poniższych cukrach prostych:
a) C4H8O4
b)C5H10O5
c)C6H12O6
x - razy
a) C x 4 x 12 + H x 8 x 1 + O x 4 x 16 = C48 + H8 + O64
b) C x 5 x 12 + H x 10 x 1 + O x 5 x 16 = C60 + H10 + O80
c) C x 6 x 12 + H x 12 x 1 + O x 6 z 16 = C72 + H12 + O96
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x - razy
a) C x 4 x 12 + H x 8 x 1 + O x 4 x 16 = C48 + H8 + O64
b) C x 5 x 12 + H x 10 x 1 + O x 5 x 16 = C60 + H10 + O80
c) C x 6 x 12 + H x 12 x 1 + O x 6 z 16 = C72 + H12 + O96