Ustal dla jakiej wartosci parametru m liczby m-5; m-1; 2m+2 w tej kolejnosci tworza ciag geometryczny
a1=m-5
a2=m-1
a3=2m+2
a3/a2=a2/a1
(2m+2)/(m-1)=(m-1)/(m-5)
(m-1)²=(2m+2)(m-5)
m²-2m+1=2m²-10m+2m-10
m²-2m+1=2m²-8m-10
m²-2m+1-2m²+8m+10=0
-m²+6m+11=0
Δ=36-4*(-1)*11=36+4*11=36+44=80
√Δ=4√5
m1=(-6-4√5)/-2=3+2√5
m2=(-6+4√5)/-2=3-2√5
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a1=m-5
a2=m-1
a3=2m+2
a3/a2=a2/a1
(2m+2)/(m-1)=(m-1)/(m-5)
(m-1)²=(2m+2)(m-5)
m²-2m+1=2m²-10m+2m-10
m²-2m+1=2m²-8m-10
m²-2m+1-2m²+8m+10=0
-m²+6m+11=0
Δ=36-4*(-1)*11=36+4*11=36+44=80
√Δ=4√5
m1=(-6-4√5)/-2=3+2√5
m2=(-6+4√5)/-2=3-2√5
licze na naj