" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
p+l=14
l=14-p
p^2+l^2=100
p^2 + 196-28p+p^2 = 100
2p^2 -28p + 96 = 0
p^2 - 14p + 48 =0
(p-8) (p-6) = 0
ukuran kandang p=8 , l=6
l = 14 - p
diagonal = 10, dg pytagoras:
p^2+l^2 = 100
p^2 + (14-p)^2 = 100
p^2 + (14-p)(14-p) = 100
p^2 + 196 - 28p + p^2 = 100
2p^2 - 28p + 196 = 100
2p^2 - 28p + 96 = 0
p^2 - 14p + 48 = 0
(p-8)(p-6) = 0 --> p=8 atau 6
l = 14-p = 14-8 = 6
jadi ukuran kandang ayam adalah : 48 m2
p x l = 8 x 6 = 48