Respuesta:
espero que te sirva a practicar
Explicación paso a paso:
A(-7,2), B(1,8), C(4,4)
Distancia A hacia B
d = [tex]\sqrt{(x_2- x_1)^{2} +(y_2- y_1)^{2} }[/tex]
d = [tex]\sqrt{(1- (-7) )^{2} +(8-2)^{2} }[/tex]
d = [tex]\sqrt{(-8 )^{2} +(6)^{2} }[/tex]
[tex]d= \sqrt{64+36 }\\d = \sqrt{100 }\\\\d= 10[/tex]
Distancia B hacia C
d = [tex]\sqrt{(4-1 )^{2} +(4-8)^{2} }[/tex]
[tex]d = \sqrt{(3 )^{2} +(-4)^{2} }\\d = \sqrt{(9 +16 }\\\\d = \sqrt{(25) }\\\\d = 5[/tex]
Distancia A hacia C
[tex]d =\sqrt{(4- (-7) )^{2} +(4-2)^{2} }\\\\ d =\sqrt{(11)^{2} +(2)^{2} }\\\\ d =\sqrt{(121 +(4) }\\\\ d = \sqrt{(125) }\\\\d = 5\sqrt{5 }\\[/tex]
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Verified answer
Respuesta:
espero que te sirva a practicar
Explicación paso a paso:
A(-7,2), B(1,8), C(4,4)
Distancia A hacia B
d = [tex]\sqrt{(x_2- x_1)^{2} +(y_2- y_1)^{2} }[/tex]
d = [tex]\sqrt{(1- (-7) )^{2} +(8-2)^{2} }[/tex]
d = [tex]\sqrt{(1- (-7) )^{2} +(8-2)^{2} }[/tex]
d = [tex]\sqrt{(-8 )^{2} +(6)^{2} }[/tex]
[tex]d= \sqrt{64+36 }\\d = \sqrt{100 }\\\\d= 10[/tex]
Distancia B hacia C
d = [tex]\sqrt{(x_2- x_1)^{2} +(y_2- y_1)^{2} }[/tex]
d = [tex]\sqrt{(4-1 )^{2} +(4-8)^{2} }[/tex]
[tex]d = \sqrt{(3 )^{2} +(-4)^{2} }\\d = \sqrt{(9 +16 }\\\\d = \sqrt{(25) }\\\\d = 5[/tex]
Distancia A hacia C
d = [tex]\sqrt{(x_2- x_1)^{2} +(y_2- y_1)^{2} }[/tex]
[tex]d =\sqrt{(4- (-7) )^{2} +(4-2)^{2} }\\\\ d =\sqrt{(11)^{2} +(2)^{2} }\\\\ d =\sqrt{(121 +(4) }\\\\ d = \sqrt{(125) }\\\\d = 5\sqrt{5 }\\[/tex]