Uporządkuj rosnąco a,b,c , jeżeli
+_____________
Dla b>0 mamy
b,a,c
Dla b<0 mamy
c,a,b
c
-------- = 2 ⇒ c = 2a + 2b
a + b
-------- = 3 ⇒ c = 3a - 3b
a - b
Czyli 2a + 2b = 3a - 3b
-a = -5b /·(-1)
a = 5b
c = 2· 5b + 2b = 10b + 2b = 12b
Odp. Liczby a, b, c, w kolejnosci rosnacej to: b < a < c (gdy b > 0)
lub c < a < b (gdy b < 0).
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+_____________
Dla b>0 mamy
b,a,c
Dla b<0 mamy
c,a,b
c
-------- = 2 ⇒ c = 2a + 2b
a + b
c
-------- = 3 ⇒ c = 3a - 3b
a - b
Czyli 2a + 2b = 3a - 3b
-a = -5b /·(-1)
a = 5b
c = 2· 5b + 2b = 10b + 2b = 12b
Odp. Liczby a, b, c, w kolejnosci rosnacej to: b < a < c (gdy b > 0)
lub c < a < b (gdy b < 0).