Untuk membuat larutan penyangga yang mempunyai ph=4 . maka kedalam 100 ml larutan ch3cooh 0,5 M (ka=10^-5 ) harus ditambahkan larutan ch3cooh 0,5 M sebanyak??
mohon bantuan nya: )
mohon bantuan nya: )
fatihahalhusna
![\displaystyle pH=4\rightarrow [H^+]=10^{-4}\ M\\\\{[H^+]}=K_a\cdot\frac{mol\ CH_3COOH}{mol\ CH_3COOBa}\\\\10^{-4}=10^{-5}\cdot\frac{100\cdot0,5}{V\cdot0,5}\\\\V=\boxed{\boxed{\bold{10\ mL}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle+pH%3D4%5Crightarrow+%5BH%5E%2B%5D%3D10%5E%7B-4%7D%5C+M%5C%5C%5C%5C%7B%5BH%5E%2B%5D%7D%3DK_a%5Ccdot%5Cfrac%7Bmol%5C+CH_3COOH%7D%7Bmol%5C+CH_3COOBa%7D%5C%5C%5C%5C10%5E%7B-4%7D%3D10%5E%7B-5%7D%5Ccdot%5Cfrac%7B100%5Ccdot0%2C5%7D%7BV%5Ccdot0%2C5%7D%5C%5C%5C%5CV%3D%5Cboxed%7B%5Cboxed%7B%5Cbold%7B10%5C+mL%7D%7D%7D "\displaystyle pH=4\rightarrow [H^+]=10^{-4}\ M\\\\{[H^+]}=K_a\cdot\frac{mol\ CH_3COOH}{mol\ CH_3COOBa}\\\\10^{-4}=10^{-5}\cdot\frac{100\cdot0,5}{V\cdot0,5}\\\\V=\boxed{\boxed{\bold{10\ mL}}}")
6 votes
Thanks 12
ditapamela
Kak fatiha Mau Gak Bantuin soal kimia ku tapi bantuinnya di sosmed WA gitu kak please mau ya kak