Una persona suelta una moneda de 7.3g en un pozo y esta tarda 2.5 s en llegar al fondo Determina la profundidad del pozo Velocidad con la que esta impacta Energía mecánica de la moneda
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Explicacion m = 7.3 g = 0.0073 kg t = 2.5 s h = ? g = 10 m/s² Vf = ? Em = ? Formula h = g t² / 2 = (10 m/s²) (2.5 s)² / 2 = 31.25 m Vf = g t = 10 m/s² (2.5 s) = 25 m/s Ep = m g h = (0.0073 kg)(10 m/s²)( 31.25 m) = 2.281 Joule Ec = m v² / 2 = (0.0073 kg) (25 m/s)² / 2 = 2.281 Joule Em = Ep + Ec = 2.281 Joule + 2.281 Joule = 4.562 Joule
m = 7.3 g = 0.0073 kg
t = 2.5 s
h = ?
g = 10 m/s²
Vf = ?
Em = ?
Formula
h = g t² / 2 = (10 m/s²) (2.5 s)² / 2 = 31.25 m
Vf = g t = 10 m/s² (2.5 s) = 25 m/s
Ep = m g h = (0.0073 kg)(10 m/s²)( 31.25 m) = 2.281 Joule
Ec = m v² / 2 = (0.0073 kg) (25 m/s)² / 2 = 2.281 Joule
Em = Ep + Ec = 2.281 Joule + 2.281 Joule = 4.562 Joule