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Oxigeno = (100 - 9.1) = 90.9 %
O= 9.1 g/ 16 g/mol = 0.5688 mol
Br: 90.9 g / 80 g/mol = 1.1363 mol
dividir entre el menor de los resultados
Br: 1.1688 mol / 0.5688 mol = 2
O: 1.1363 mol / 1.1363 mol = 1
FE= Br2O (OXIDO DE BROMO I )