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C: 85.63 g / 12 g/mol = 7.14 mol
H: 14.37 g / 1 g/mol = 14.37 mol
dividir entre el menor de los resultados
C: 7.14 mol / 7.14 mol = 1
H:14.34 mol / 7.14 mol = 2
FE: CH2
Mm de la FE
C: 1 x 12 = 12 g/mol
H: 2 x 1 = 2 g/mol
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Mm = 14 g/mol
n = 42 g/mol / 14 g/mol
n = 3
FM = (FE)n
FM = (CH2)3 = C3H6 (PROPENO)