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tb: tiempo de caño b.
tb = ta +2
1h20 = 4/3 h
4/3 = ta*tb/(ta+tb)
4/3 = ta(2+ta)/(2ta + 2)
8+8ta = 3ta² + 6ta
3ta² - 2ta - 8 = 0
(ta-2)(3ta+4) = 0
Se elige ta>0; es decir ta = 2
tb = 2 + 2 = 4
El caño a tarda 2 horas y el caño b tarda 4 horas.