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AB = 150
AC = 300
ABC (b) = 40º
CALCULAR
BC= ?
ACB (c)= ?
Por el teorema de los senos
AC/sen(b) = AB/sen (c)
despejando y añadiendo valores
sen(c) = 150*sen (40)/300
c = 18º45'
calculamos a = 180 - 18º45' - 40º
a= 121º15'
por teorema de senos
BC/ sen (a) = AC / sen (b)
despejando
BC = 300 sen 121º15' / sen 40
BC = 399 millas