Układy równań. Zrobi ktoś to zadanie 9 w załączniku ? Tylko nie metodą przeciwnych współczynników ja.... Question from @Magdziocha4

January 2019 1 5 Report

Układy równań. Zrobi ktoś to zadanie 9 w załączniku ? Tylko nie metodą przeciwnych współczynników jak jest w poleceniu tylko metodą podstawienia bo tak pani kazała. BŁAGAM!

wariattka Zad. 9
a.)
$\left \{ {{3x+y=5} \atop {2x-y=0}} \right.$

$\left \{ {{y=5-3x} \atop {2x-y=0}} \right.$

$\left \{ {{y=5-3x} \atop {2x-(5-3x)=0}} \right.$

$\left \{ {{y=5-3x} \atop {2x-5+3x=0}} \right.$

$\left \{ {{y=5-3x} \atop {2x+3x=5}} \right.$

$\left \{ {{y=5-3x} \atop {5x=5 /:5}} \right.$

$\left \{ {{y=5-3x} \atop {x=1}} \right.$

$\left \{ {{y=5-3*1} \atop {x=1}} \right.$

$\left \{ {{y=5-3} \atop {x=1}} \right.$

$\left \{ {{y=2} \atop {x=1}} \right.$

b.)
$\left \{ {{2x-y=5} \atop {x+y=4}} \right.$

$\left \{ {{2x-y=5} \atop {x=4-y}} \right.$

$\left \{ {{2(4-y)-y=5} \atop {x=4-y}} \right.$

$\left \{ {{8-2y-y=5} \atop {x=4-y}} \right.$

$\left \{ {{-2y-y=5-8} \atop {x=4-y}} \right.$

$\left \{ {{-3y=-3 /:(-3)} \atop {x=4-y}} \right.$

$\left \{ {{y=1} \atop {x=4-y}} \right.$

$\left \{ {{y=1} \atop {x=4-1}} \right.$

$\left \{ {{y=1} \atop {x=3}} \right.$

c.)
$\left \{ {{-x-y=-6} \atop {-x+y=2}} \right.$

$\left \{ {{-x-y=-6} \atop {y=2+x}} \right.$

$\left \{ {{-x-(2+x)=-6} \atop {y=2+x}} \right.$

$\left \{ {{-x-2-x=-6} \atop {y=2+x}} \right.$

$\left \{ {{-x-x=-6+2} \atop {y=2+x}} \right.$

$\left \{ {{-2x=-4 /:(-2)} \atop {y=2+x}} \right.$

$\left \{ {{x=2} \atop {y=2+x}} \right.$

$\left \{ {{x=2} \atop {y=2+2}} \right.$

$\left \{ {{x=2} \atop {y=4}} \right.$

d.)
$\left \{ {{4x-5y=-4} \atop {-2x+3y=1,1}} \right.$

$\left \{ {{4x=-4+5y /:4} \atop {-2x+3y=1,1}} \right.$

$\left \{ {{x= \frac{-4+5y}{4} } \atop {-2x+3y=1,1}} \right.$

$\left \{ {{x= \frac{-4+5y}{4} } \atop {-2* \frac{-4+5y}{4}+3y=1,1 }} \right.$

$\left \{ {{x= \frac{-4+5y}{4} } \atop { \frac{8-10y}{4}+3y=1,1 /*4 }} \right.$

$\left \{ {{x= \frac{-4+5y}{4} } \atop {8-10y+12y=4,4}} \right.$

$\left \{ {{x= \frac{-4+5y}{4} } \atop {-10y+12y=4,4-8}} \right.$

$\left \{ {{x= \frac{-4+5y}{4} } \atop {2y=-3,6 /:2}} \right.$

$\left \{ {{x= \frac{-4+5y}{4} } \atop {y=-1,8}} \right.$

$\left \{ {{x= \frac{-4+5*(-1,8)}{4} } \atop {y=-1,8}} \right.$

$\left \{ {{x= \frac{-4-9}{4} } \atop {y=-1,8}} \right.$

$\left \{ {{x= \frac{-13}{4} } \atop {y=-1,8}} \right.$

$\left \{ {{x=-3,25} \atop {y=-1,8}} \right.$

e.)
$\left \{ {{-2x+y=0} \atop {3x-3y=1}} \right.$

$\left \{ {{y=2x} \atop {3x-3y=1}} \right.$

$\left \{ {{y=2x} \atop {3x-3*2x=1}} \right.$

$\left \{ {{y=2x} \atop {3x-6x=1}} \right.$

$\left \{ {{y=2x} \atop {-3x=1 /:(-3)}} \right.$

$\left \{ {{y=2x} \atop {x=- \frac{1}{3} }} \right.$

$\left \{ {{y=2*(- \frac{1}{3}) } \atop {x=- \frac{1}{3} }} \right.$

$\left \{ {{y=- \frac{2}{3} } \atop {x=- \frac{1}{3} }} \right.$

f.)
$\left \{ {{3x-3y=-12} \atop {2x-5y=-19}} \right.$

$\left \{ {{3x=-12+3y /:3} \atop {2x-5y=-19}} \right.$

$\left \{ {{x= \frac{-12+2y}{3} } \atop {2x-5y=-19}} \right.$

$\left \{ {{x= \frac{-12+2y}{3} } \atop {2* \frac{-12+2y}{3}-5y=-19 }} \right.$

$\left \{ {{x= \frac{-12+2y}{3} } \atop { \frac{-24+4y}{3}-5y=-19 /*3 }} \right.$

$\left \{ {{x= \frac{-12+2y}{3} } \atop {-24+4y-15y=-57}} \right.$

$\left \{ {{x= \frac{-12+2y}{3} } \atop {4y-15y=-57+24}} \right.$

$\left \{ {{x= \frac{-12+2y}{3} } \atop {-11y=-33 /:(-11)}} \right.$

$\left \{ {{x= \frac{-12+2y}{3} } \atop {y=3}} \right.$

$\left \{ {{x= \frac{-12+2*3}{3} } \atop {y=3}} \right.$

$\left \{ {{x= \frac{-12+6}{3} } \atop {y=3}} \right.$

$\left \{ {{x= \frac{-6}{3} } \atop {y=3}} \right.$

$\left \{ {{x=-2} \atop {y=3}} \right.$

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