Question

Tulislah persamaan garis lurus yg melalui titik (12,3)dan(8,1)

Answer 1

y -y₁    =    x -x₁
y₂ -y₁        x₂ -x₁

y -3    =  x -12
1 -3        8 -12

y -3 = x -12
 -2        -4

-4(y -3) = -2(x -12)
-4y +12 = -2x +24
-4y = -2x +24 -12
-4y = -2x +12
2x -4y -12 = 0

Answer 2

(12,3) dan (8,1)



-4y +12 = 2x - 24
-4y +12 - 2x + 24=0
-4y-2x+36=0
--------------------÷-2
2y+x-18=0
atw
2y+x=18