Penjelasan dengan langkah-langkah:
14] sin a = 1/√10 → y/r
x = √(r² - y²)
x = √(√10² - 1²)
x = √(10 - 1)
x = √9
x = 3
tan a = y/x
tan a = 1/3
15] BC/sin A = AB/sin C
(6 √2)/sin 45° = 6/sin C
sin C = (1/2 √2 . 6)/(6 √2)
sin C = 1/2
Sudut C = 30°
Sudut B
= 180° - 30° - 45°
= 105°
16] sin 45° . cos 45° . cos 60° + cos 90°
= 1/√2 . 1/√2 . 1/2 + 0
= 1/2 . 1/2
= 1/4
17] cos 1.230°
= cos (3 . 360° + 150°)
= cos 150°
= -1/2 √3
18] 1/5 . π rad
= 1/5 . π . 180°/π
= 180°/5
= 36°
19] 45,55°
= 45° + 0,55°
= 45° + 0,55 . 60'
= 45° + 33'
= 45° 33'
Jawaban terlampir
jangan lupa folownya ya
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Penjelasan dengan langkah-langkah:
14] sin a = 1/√10 → y/r
x = √(r² - y²)
x = √(√10² - 1²)
x = √(10 - 1)
x = √9
x = 3
tan a = y/x
tan a = 1/3
15] BC/sin A = AB/sin C
(6 √2)/sin 45° = 6/sin C
sin C = (1/2 √2 . 6)/(6 √2)
sin C = 1/2
Sudut C = 30°
Sudut B
= 180° - 30° - 45°
= 105°
16] sin 45° . cos 45° . cos 60° + cos 90°
= 1/√2 . 1/√2 . 1/2 + 0
= 1/2 . 1/2
= 1/4
17] cos 1.230°
= cos (3 . 360° + 150°)
= cos 150°
= -1/2 √3
18] 1/5 . π rad
= 1/5 . π . 180°/π
= 180°/5
= 36°
19] 45,55°
= 45° + 0,55°
= 45° + 0,55 . 60'
= 45° + 33'
= 45° 33'
Jawaban terlampir
jangan lupa folownya ya