Question

tugas math dari Miss Arimbi terlampir diatas
bantu jan liatin doank​

Answer 1

1. Sejajar dengan
4x+y+20 = 0
y = -4x-20
m = -4
Dan memotong pd
(2, 0) x₁ = 2, y₁ = 0
Pers. garis =
y-y₁ = m(x-x₁)
y-0 = -4(x-2)
y = -4x+8
4x + y - 8 = 0 (a.)
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2. Tentukan HP dari
3x + y = 7 (·1) 3x +     y = 7
x + 4y = 6 (·3) 3x+12y = 18
Eliminasi
12y-y = 18-7
11y = 11
y = 1
x + 4y = 6, x + 4(1) = 6
x = 6-4,
x = 2
HP = {x, y}
HP = {2, 1} (b)

Answer 2

Jawaban:

1) 4x + y + 20 = 0

y = mx + c

y = -4x - 20

m = -4

garis sejajar m2 = m1

m2 = -4

persamaan garis lurus baru melalui (2,0)

(y - q) = m2(x - p)

(y - 0) = -4 ( x - 2)

y -0 = -4x + 8

-4x + 8 + y + 0 = 0

-4x + y + 8 = 0 (option D)

2) 3x + y = 7 | x 1

x + 4y = 6 | x 3

3x + y = 7

3x + 12y = 18 -

- 11y = -11

y = -11/-11

y = 1

3x + y = 7

3x + 1 = 7

3x = 7 -1

3x = 6

x = 6/3

x = 2

HP = {2,1} (option B)

3) 2x + 3y = 20 | x 3

3x + 5y = 15. | x 2

6x + 9y = 60

6x + 10y = 30 -

-y = 30

y = -30

2x + 3y = 20

2x + 3(-30) = 20

2x -90 = 20

2x = 20 + 90

2x = 110

x = 110/2

x = 55

x + 2y = 55 + 2(-30)

= 55 - 60

= -5

Semoga membantu dan tidak keliru