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a₂/a₁=a₃/a₂
a₂²=a₁a₃
a₂/a₁=(a₃+1)/a₂
a₂²=a₁(a₃+1)
a₁a₃=a₁a₃+a₁
a₁=1
1+a₂+a₃=6
a₂+a₃=5
a₂=5-a₃
(5-a₃)²=a₃+1
25-10a₃+a₃²=a₃+1
a₃²-11a₃+24=0
Δ=b²-4ac=121-96=25
√Δ=5
a₃=(11-5)/2=3
a₂=5-3=2
to liczby:
1;2;3
Załącznik: