Trudne zadania , (5) w załączniku mają być zrobione bez błędów , bo od tego zależy czy zdam do następnej klasy. (1gimnazjum)
krysta
![=2[4-4*( -\frac{5}{2} ]-4 -3*5 =2[4+10]-4 -3*5 =\\\\=2*14-4 -15 =28-4-15=9](https://tex.z-dn.net/?f=%3D2%5B4-4%2A%28+-%5Cfrac%7B5%7D%7B2%7D+%5D-4+-3%2A5+%3D2%5B4%2B10%5D-4+-3%2A5+%3D%5C%5C%5C%5C%3D2%2A14-4+-15+%3D28-4-15%3D9 "=2[4-4*( -\frac{5}{2} ]-4 -3*5 =2[4+10]-4 -3*5 =\\\\=2*14-4 -15 =28-4-15=9")
![zad.3)\\\\a=\frac{4}{15},\ \ b=\frac{1}{4}\\\\1-a(b-1)+2[-b(a+1)-0,5a ]+2b=\\\\=1- \frac{4}{15}*( \frac{1}{4}-1)+2[- \frac{1}{4}*( \frac{4}{15}+1)- \frac{1}{2}*\frac{4}{15} ]+2*\frac{1}{4}=\\\\=1- \frac{4}{15}*(- \frac{3}{4} )+2[- \frac{1}{4}* \frac{19}{15} - \frac{2}{15} ]+ \frac{1}{2}=](https://tex.z-dn.net/?f=zad.3%29%5C%5C%5C%5Ca%3D%5Cfrac%7B4%7D%7B15%7D%2C%5C+%5C+b%3D%5Cfrac%7B1%7D%7B4%7D%5C%5C%5C%5C1-a%28b-1%29%2B2%5B-b%28a%2B1%29-0%2C5a+%5D%2B2b%3D%5C%5C%5C%5C%3D1-+%5Cfrac%7B4%7D%7B15%7D%2A%28+%5Cfrac%7B1%7D%7B4%7D-1%29%2B2%5B-+%5Cfrac%7B1%7D%7B4%7D%2A%28+%5Cfrac%7B4%7D%7B15%7D%2B1%29-+%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B4%7D%7B15%7D+%5D%2B2%2A%5Cfrac%7B1%7D%7B4%7D%3D%5C%5C%5C%5C%3D1-+%5Cfrac%7B4%7D%7B15%7D%2A%28-+%5Cfrac%7B3%7D%7B4%7D+%29%2B2%5B-+%5Cfrac%7B1%7D%7B4%7D%2A+%5Cfrac%7B19%7D%7B15%7D+-+%5Cfrac%7B2%7D%7B15%7D+%5D%2B+%5Cfrac%7B1%7D%7B2%7D%3D "zad.3)\\\\a=\frac{4}{15},\ \ b=\frac{1}{4}\\\\1-a(b-1)+2[-b(a+1)-0,5a ]+2b=\\\\=1- \frac{4}{15}*( \frac{1}{4}-1)+2[- \frac{1}{4}*( \frac{4}{15}+1)- \frac{1}{2}*\frac{4}{15} ]+2*\frac{1}{4}=\\\\=1- \frac{4}{15}*(- \frac{3}{4} )+2[- \frac{1}{4}* \frac{19}{15} - \frac{2}{15} ]+ \frac{1}{2}=")
![=1+ \frac{1}{ 5} +2*[- \frac{1}{4}* \frac{19}{15} - \frac{2}{15} ]+ \frac{1}{2}=\\\\= 1+ \frac{1}{ 5} +2*[- \frac{19}{60} - \frac{8}{60} ]+ \frac{1}{2}= 1 \frac{1}{ 5} - \frac{27}{30} + \frac{1}{2}= 1 \frac{6}{ 30} - \frac{27}{30} + \frac{15}{30}= 1 \frac{6}{ 30} - \frac{27}{30} + \frac{15}{30}=\frac{24}{30}=\frac{4}{5}](https://tex.z-dn.net/?f=%3D1%2B+%5Cfrac%7B1%7D%7B+5%7D+%2B2%2A%5B-+%5Cfrac%7B1%7D%7B4%7D%2A+%5Cfrac%7B19%7D%7B15%7D+-+%5Cfrac%7B2%7D%7B15%7D+%5D%2B+%5Cfrac%7B1%7D%7B2%7D%3D%5C%5C%5C%5C%3D+1%2B+%5Cfrac%7B1%7D%7B+5%7D+%2B2%2A%5B-+%5Cfrac%7B19%7D%7B60%7D+-+%5Cfrac%7B8%7D%7B60%7D+%5D%2B+%5Cfrac%7B1%7D%7B2%7D%3D+1+%5Cfrac%7B1%7D%7B+5%7D+-+%5Cfrac%7B27%7D%7B30%7D+%2B+%5Cfrac%7B1%7D%7B2%7D%3D+1+%5Cfrac%7B6%7D%7B+30%7D+-+%5Cfrac%7B27%7D%7B30%7D+%2B+%5Cfrac%7B15%7D%7B30%7D%3D+1+%5Cfrac%7B6%7D%7B+30%7D+-+%5Cfrac%7B27%7D%7B30%7D+%2B+%5Cfrac%7B15%7D%7B30%7D%3D%5Cfrac%7B24%7D%7B30%7D%3D%5Cfrac%7B4%7D%7B5%7D "=1+ \frac{1}{ 5} +2*[- \frac{1}{4}* \frac{19}{15} - \frac{2}{15} ]+ \frac{1}{2}=\\\\= 1+ \frac{1}{ 5} +2*[- \frac{19}{60} - \frac{8}{60} ]+ \frac{1}{2}= 1 \frac{1}{ 5} - \frac{27}{30} + \frac{1}{2}= 1 \frac{6}{ 30} - \frac{27}{30} + \frac{15}{30}= 1 \frac{6}{ 30} - \frac{27}{30} + \frac{15}{30}=\frac{24}{30}=\frac{4}{5}")
![zad.4)\\\\x=-\frac{1}{6},\ \ \ y=-4\\\\3x(-5+y)-5[-3x+2(y-1)]-10(5y-4)= \\\\=3*(-\frac{1}{6})*(-5-4)-5*[-3*(-\frac{1}{6})+2*(-4-1)]-10*(5*(-4)-4)=\\\\= (- \frac{1}{2} )*(-9)-5*[ \frac{1}{2}+2* (-5)]-10*( -20-4)=](https://tex.z-dn.net/?f=zad.4%29%5C%5C%5C%5Cx%3D-%5Cfrac%7B1%7D%7B6%7D%2C%5C+%5C+%5C+y%3D-4%5C%5C%5C%5C3x%28-5%2By%29-5%5B-3x%2B2%28y-1%29%5D-10%285y-4%29%3D+%5C%5C%5C%5C%3D3%2A%28-%5Cfrac%7B1%7D%7B6%7D%29%2A%28-5-4%29-5%2A%5B-3%2A%28-%5Cfrac%7B1%7D%7B6%7D%29%2B2%2A%28-4-1%29%5D-10%2A%285%2A%28-4%29-4%29%3D%5C%5C%5C%5C%3D+%28-+%5Cfrac%7B1%7D%7B2%7D+%29%2A%28-9%29-5%2A%5B+%5Cfrac%7B1%7D%7B2%7D%2B2%2A+%28-5%29%5D-10%2A%28+-20-4%29%3D "zad.4)\\\\x=-\frac{1}{6},\ \ \ y=-4\\\\3x(-5+y)-5[-3x+2(y-1)]-10(5y-4)= \\\\=3*(-\frac{1}{6})*(-5-4)-5*[-3*(-\frac{1}{6})+2*(-4-1)]-10*(5*(-4)-4)=\\\\= (- \frac{1}{2} )*(-9)-5*[ \frac{1}{2}+2* (-5)]-10*( -20-4)=")
![= \frac{9}{2} -5*[ \frac{1}{2}- \frac{20}{2}]-10*( -24)= \frac{9}{2} -5*( - \frac{19}{2})+240 =\frac{9}{2} + \frac{95}{2} +240= \\\\=\frac{104}{2}+240=52+240=292](https://tex.z-dn.net/?f=%3D+%5Cfrac%7B9%7D%7B2%7D+-5%2A%5B+%5Cfrac%7B1%7D%7B2%7D-+%5Cfrac%7B20%7D%7B2%7D%5D-10%2A%28+-24%29%3D+%5Cfrac%7B9%7D%7B2%7D+-5%2A%28+-+%5Cfrac%7B19%7D%7B2%7D%29%2B240+%3D%5Cfrac%7B9%7D%7B2%7D+%2B+%5Cfrac%7B95%7D%7B2%7D+%2B240%3D+%5C%5C%5C%5C%3D%5Cfrac%7B104%7D%7B2%7D%2B240%3D52%2B240%3D292 "= \frac{9}{2} -5*[ \frac{1}{2}- \frac{20}{2}]-10*( -24)= \frac{9}{2} -5*( - \frac{19}{2})+240 =\frac{9}{2} + \frac{95}{2} +240= \\\\=\frac{104}{2}+240=52+240=292")
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