tresc w załączniku.prosze o pomoc.potrzebuje to na jutro
a)2(2x-3)(x+1)-5(x-1)^2=2(x-2)(x-1)
2(2x^2+2x-3x-3)-5(x^2-2x+1)=2(x^2-x-2x+2)
4x^2+4x-6x-6-5x^2+10x-5=2x^2-2x-4x+4
-x^2+8x-11=2x^2-6x+4
-3x^2+14x-15=0
delta=196-180=16
pierwiastek z delty=4
x1=-14+16/-6=-1/3
x2=-14-16/-6=5
b) -x^2-3x+4>0
delta=9+16=25
pierwiastek z delty=5
x1=3+5/-2=-4
x2=3-5/-2=1
c)x^2-7x+12>0
delta=49-48=1
pierwiastek z delty=1
x1=7+1/2=4
x2=7-1/2=3
metoda podstawiania:
a) 3x-2y=0 => 2y=3x => 2y=3*-4
6y-10x=4 => 3(3x)-10x=4 2y=-12/:2
9x-10x=4 y=-6
-x=4
x=-4
b) x(x+1)-(x+2)^2=y-3
1/2x-1/4y=4 /*4
x^2+x-(x^2+4x+4)=y-3
2x-y=4
x^2+x-x^2-4x-4=y-3
-3x-y=1 => y=-3x-1 => y=-3*3/5-1
2x-y=4 => 2x-(-3x-1)=4 y=-9/5-1
2x+3x+1=4 y=-14/5
5x=3/:5
x=3/5
Rozwiaz rownania i nierownosci:a)2(2x-3)(x+1)-5(x-1)2=2(x-2)(x-1)2(2x²+2x-3x-3)-(5x+5)2=2(x²-x-2x+2)
4x²+4x-6x-6-10x-10=2x²-2x-4x+4
4x²-2x²+4x-6x-10x+2x+4x-6-10-4=0
2x²-6x-20=0
a=2 b=-6 c=-20
Δ=b²-4*a*c= (-6)²-4*2*(-20)=36+160=169
√Δ=14
x₁=-b-√Δ /2a = 6-14 /4= -8/4=-2 /--kreska ułamkowa
x₂=-b+√Δ /2a= 6+14 /4= 20/4=5
b) -x²-3x+4>0
a=-1 b=-3 c=4
Δ=b²-4*a*c= (-3)²-4*(-1)*4=9+16=25
√Δ=5
x₁=-b-√Δ /2a> 3-5 /-2 > -2/-2< 1 /-kreska ułamkowa
x₂=-b+√Δ /2a>3+5/-2> 8/-2< -4
c) x²-7x+12>0
a=1 b=-7 c=12
Δ=b²-4*a*c= (-7)²-4*1*12=49-48=1
√Δ=1
x₁=-b-√Δ /2a> 7-1 /2> 6/2> 3
x₂=-b+√Δ/2a>7+1/2 >8/2> 4
rozwiaz uklady rownan metoda podstawiania
a) {3x-2y=0 {6y-10x=4 /:2
{3x-2y=0
{3y-5x=4
-2y=-3:(-2)
y=³/₂
3y-5x=4
3*³/₂ -5x=4
⁹/₂ -5x=4
-5x=4-⁹/₂
-5x= -½ /:(-1)
5x= ½ /: 5
x= ¹/₁₀
3*¹/₁₀ -2y=0
³/₁₀ -2y=0
-2y= -³/₁₀ /:(-2)
{y= ³/₂₀
{x= ¹/₁₀
b) {x(x+1)-(x+2)²=y-3 {½x - ¼y=4
{x²+x-(x²+4x+4)=y-3
{½x - ¼y=4
{x²+x-x²-4x-4=y-3
{-3x-y=1
-y=1+3x
½x - ¼y=4
½x - ¼*(1+3x)=4
½x - ¼+¾x=4
⁵/₄x= ¹⁷/₄ /:⁵/₄
x= 3⅖
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a)2(2x-3)(x+1)-5(x-1)^2=2(x-2)(x-1)
2(2x^2+2x-3x-3)-5(x^2-2x+1)=2(x^2-x-2x+2)
4x^2+4x-6x-6-5x^2+10x-5=2x^2-2x-4x+4
-x^2+8x-11=2x^2-6x+4
-3x^2+14x-15=0
delta=196-180=16
pierwiastek z delty=4
x1=-14+16/-6=-1/3
x2=-14-16/-6=5
b) -x^2-3x+4>0
delta=9+16=25
pierwiastek z delty=5
x1=3+5/-2=-4
x2=3-5/-2=1
c)x^2-7x+12>0
delta=49-48=1
pierwiastek z delty=1
x1=7+1/2=4
x2=7-1/2=3
metoda podstawiania:
a) 3x-2y=0 => 2y=3x => 2y=3*-4
6y-10x=4 => 3(3x)-10x=4 2y=-12/:2
9x-10x=4 y=-6
-x=4
x=-4
b) x(x+1)-(x+2)^2=y-3
1/2x-1/4y=4 /*4
x^2+x-(x^2+4x+4)=y-3
2x-y=4
x^2+x-x^2-4x-4=y-3
2x-y=4
-3x-y=1 => y=-3x-1 => y=-3*3/5-1
2x-y=4 => 2x-(-3x-1)=4 y=-9/5-1
2x+3x+1=4 y=-14/5
5x=3/:5
x=3/5
Rozwiaz rownania i nierownosci:
a)2(2x-3)(x+1)-5(x-1)2=2(x-2)(x-1)
2(2x²+2x-3x-3)-(5x+5)2=2(x²-x-2x+2)
4x²+4x-6x-6-10x-10=2x²-2x-4x+4
4x²-2x²+4x-6x-10x+2x+4x-6-10-4=0
2x²-6x-20=0
a=2 b=-6 c=-20
Δ=b²-4*a*c= (-6)²-4*2*(-20)=36+160=169
√Δ=14
x₁=-b-√Δ /2a = 6-14 /4= -8/4=-2 /--kreska ułamkowa
x₂=-b+√Δ /2a= 6+14 /4= 20/4=5
b) -x²-3x+4>0
a=-1 b=-3 c=4
Δ=b²-4*a*c= (-3)²-4*(-1)*4=9+16=25
√Δ=5
x₁=-b-√Δ /2a> 3-5 /-2 > -2/-2< 1 /-kreska ułamkowa
x₂=-b+√Δ /2a>3+5/-2> 8/-2< -4
c) x²-7x+12>0
a=1 b=-7 c=12
Δ=b²-4*a*c= (-7)²-4*1*12=49-48=1
√Δ=1
x₁=-b-√Δ /2a> 7-1 /2> 6/2> 3
x₂=-b+√Δ/2a>7+1/2 >8/2> 4
rozwiaz uklady rownan metoda podstawiania
a) {3x-2y=0
{6y-10x=4 /:2
{3x-2y=0
{3y-5x=4
-2y=-3:(-2)
{3y-5x=4
y=³/₂
3y-5x=4
3*³/₂ -5x=4
⁹/₂ -5x=4
-5x=4-⁹/₂
-5x= -½ /:(-1)
5x= ½ /: 5
x= ¹/₁₀
3*¹/₁₀ -2y=0
³/₁₀ -2y=0
-2y= -³/₁₀ /:(-2)
{y= ³/₂₀
{x= ¹/₁₀
b) {x(x+1)-(x+2)²=y-3
{½x - ¼y=4
{x²+x-(x²+4x+4)=y-3
{½x - ¼y=4
{x²+x-x²-4x-4=y-3
{½x - ¼y=4
{-3x-y=1
{½x - ¼y=4
-y=1+3x
½x - ¼y=4
½x - ¼*(1+3x)=4
½x - ¼+¾x=4
⁵/₄x= ¹⁷/₄ /:⁵/₄
x= 3⅖