Question

Tolongin donggg
nomor 1a, 3 dan 4
please bgttt

Answer 1

1a. 32^(4/5). (1/3)^-3 . 16^(-7/4)
=2^(5.4/5) . 1/3^-3 . 2^(4.-7/4)
=2^4 . 3^3. 2^-7
=2^(4-7) . 27 = 2^-3 . 27 = 1/8 . 27
= 27/8 = 3 3/8 = 3,375
3.
(2^(2.(n+2))- 2^2 . 2^2n )/2^n .2^(n+2)
=(2^(2n+4) -2^2. 2^2n) / 2^(n+(n+2))
=(2^(2n+4)-2^(2+2n)) / 2^(2n+2)
=2^(2n+4)÷2^(2n+2) - 1
=2^(2n+4-(2n+2)) - 1 = 2^2 - 1 = 4 - 1
= 3
4.
* √(54+14√(5)) = √(54+2√(245))
= √(49)+√(5)
**√(12-2√(35)) = √(7) - √(5)
*** √(32-10√(7)) = √(32-2√(175))
=√(25) - √(7)
jadi:
√(54+14√(5)) + √(12-2√(35)) + √(32-10√(7))
= √(49)+√(5) + √(7) - √(5) + √(25) - √(7)
=7 + 5 =12