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p.rusuk balok = 4.(p+l+t)
= 4.(17+10+8)
= 4.35
= 140 cm
jadi, sisa kawat = 600 - 140 = 460 cm
2) l² = p² - ( r1-r2)²
24² = 25² - (16-r2)²
576 = 625 - (16-r2)²
(15-r2)² = 625 - 576
(15-r2)² = 49
15-r2 = √49
15-r2 = 7
-r2 = 7-15
-r2 = -8
r2 = 8