Question

Tolong yg pandai mtk​

Answer 1

Diketahui:

lim ³√(ax+b)/(x+1) = 2

Ditanyakan:

lim (³√((ax/8)+(6/8))-2x+1)/(x²+4x+3)

Jawab:

lim (³√((ax/8)+(b/8))-2x+1)/(x²+4x+3)

=lim ((³√(1/8))³√(ax+b)-2x+1)/(x+3)(x+1)

=lim (1/2)³√(ax+b)-(2x-1))/(x+3)(x+1)

=(1/2 lim ³√(ax+b)-(2x-1))/(x+1). 1/(x+3)

= (1/2 lim ³√(ax+b)/(x+1) - (2x-1)/(x+1)) . 1/(x+3)

= (1/2 lim ³√(ax+b)/(x+1) - lim (2x-1)/(x+1)). lim 1/(x+3)

(subtitusikan persamaan awal dan 2 ke x)

= (1/2 .(2) - (2(2)-1)/(2+1)). 1/(2+3)

= (1-(3/3)). (1/5)

= (1-1). (1/5)

= 0.(1/5)

= 0 (C)

Mapel: Matematika

Kelas: 11

Materi: Limit