Ganjar64
AC² = AB²+BC² (2x+2)² = (2x+1)²+(2x)² 4x²+8x+4 = 4x²+4x+1+4x² 4x²-4x²-4x²+8x-4x+4-1 = 0 -4x²+4x+3 = 0 (2x+1)(-2x+3) = 0 x = -1/2 atau x = 3/2 panjang tidak mungkin negatif, maka x = 3/2
panjang sisi2nya: AB = 2x+1 = 2(3/2)+1 = 3+1 = 4 BC = 2x = 2(3/2) = 3 AC = 2x+2 = 2(3/2)+2 = 3+2 = 5
(2x+2)² = (2x+1)²+(2x)²
4x²+8x+4 = 4x²+4x+1+4x²
4x²-4x²-4x²+8x-4x+4-1 = 0
-4x²+4x+3 = 0
(2x+1)(-2x+3) = 0
x = -1/2 atau x = 3/2
panjang tidak mungkin negatif, maka x = 3/2
panjang sisi2nya:
AB = 2x+1 = 2(3/2)+1 = 3+1 = 4
BC = 2x = 2(3/2) = 3
AC = 2x+2 = 2(3/2)+2 = 3+2 = 5
luas:
L = 1/2 x AB x BC
= 1/2 x 4 x 3
= 6
BC =3
AC =6
LUASNYA 6