(1) cos 72 + sin72 tan 36 = 1 cos 72 + sin 72 tan 36 = = cos 72 + sin 72 . sin 36/cos 36 = (cos 72 cos 36 + sin 72 sin 36)/cos 36 = cos (72 - 36) / cos 36 = cos 36/cos 36 = 1
(2) m = p tan α n = p tan 2α n = 2p tan α/(1 - tan² α)
(2m/n ) = 2 p tan α (1- tan² α)/(2p tan α) (2m/n ) = 1 - tan² α
Verified answer
Jawab(1)
cos 72 + sin72 tan 36 = 1
cos 72 + sin 72 tan 36 =
= cos 72 + sin 72 . sin 36/cos 36
= (cos 72 cos 36 + sin 72 sin 36)/cos 36
= cos (72 - 36) / cos 36
= cos 36/cos 36
= 1
(2)
m = p tan α
n = p tan 2α
n = 2p tan α/(1 - tan² α)
(2m/n ) = 2 p tan α (1- tan² α)/(2p tan α)
(2m/n ) = 1 - tan² α
(2m/n- 1) p² +m² = 0
(2m/n -1) p² + m² =
= (1 - tan² α - 1) p² + (p tan α) ²
= - p² tan² α + p² tan² α
= 0