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2(p+l)=70
p=35-l.....(2)
substitusikan persamaan 2 ke persamaan 1
300= (35-l).l
300= 35l-l^2
l^2-35l+300=0
(l-20)(l-15)=0
l=20cm v l=15cm
subs nilai l ke pers p=35-l
p=35-20
=15cm
p=35-15
=20cm
jadi ukuran persegi panjang itu adalah 20cm X 15 cm